Required:
Find the time difference between two dates (of following format) in seconds and in hh:mm:ss format.
e.g.
date1='Oct/09/2009 10:58:01' and
date2='Oct/10/2009 12:17:10'
find the difference between date1 and date2 in seconds(i.e. 91149 seconds) and later convert it to hh:mm:ss format (i.e. 25:19:09).
The complete python program:
import sys,time,string,getopt
def usage():
print "Usage: adbtimediff.py -f <fromTime> -t <toTime> \n"
sys.exit(2)
def parse_args():
global fromTime,toTime
fromTime = toTime = ""
try:
opts, args = getopt.getopt(sys.argv[1:], "f:t:", ["fromtime", "totime"])
except getopt.GetoptError:
print "Invalid arguments, exiting"
sys.exit(2)
for arg, val in opts:
if arg in ("-f","--fromtime"):
fromTime = val
elif arg in ("-t","--totime"):
toTime = val
if fromTime == toTime == "" :
usage()
def compute_time(time1):
t = time1.split(':')
return time.mktime(time.strptime(":".join(t[0:len(t)]),"%b/%d/%Y %H:%M:%S"))
def subtract(list):
return list[1] - list[0]
def time_convert(secs):
secs = int(secs)
mins = secs // 60
hrs = mins // 60
return "%02d:%02d:%02d" % (hrs, mins % 60, secs % 60)
def main():
parse_args()
print "Fromtime : " + str(fromTime) + '\n' + "Totime : " + str(toTime)
timelist = [ fromTime, toTime ]
s = map(compute_time,timelist)
d = subtract(s)
print "diff in seconds : " + str(d)
f = str(d).split('.')
final = time_convert(f[0])
print "Total difference in required format : " + str(final)
main()
Executing the above script:
$ python timediff.py -f 'Oct/09/2009 10:58:01' -t 'Oct/10/2009 12:17:10'
Output:
Fromtime : Oct/09/2009 10:58:01
Totime : Oct/10/2009 12:17:10
diff in seconds : 91149.0
Total difference in required format : 25:19:09
Related concepts and posts:
- Convert seconds to hh:mm:ss format using python
- Python time.mktime
- Python time.strftime
- Python map
- Python getopt
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