Python - time difference between dates

Required:

Find the time difference between two dates (of following format) in seconds and in hh:mm:ss format.

e.g.

date1='Oct/09/2009 10:58:01' and
date2='Oct/10/2009 12:17:10'

find the difference between date1 and date2 in seconds(i.e. 91149 seconds) and later convert it to hh:mm:ss format (i.e. 25:19:09).

The complete python program:

import sys,time,string,getopt

def usage():
    print "Usage: adbtimediff.py -f <fromTime> -t <toTime> \n"
    sys.exit(2)


def parse_args():
    global fromTime,toTime
    fromTime = toTime = ""

    try:
        opts, args = getopt.getopt(sys.argv[1:], "f:t:", ["fromtime", "totime"])
    except getopt.GetoptError:
        print "Invalid arguments, exiting"
        sys.exit(2)

    for arg, val in opts:
        if  arg in ("-f","--fromtime"):
            fromTime = val
        elif arg in ("-t","--totime"):
            toTime = val

    if fromTime == toTime == "" :
        usage()

def compute_time(time1):
    t = time1.split(':')
    return time.mktime(time.strptime(":".join(t[0:len(t)]),"%b/%d/%Y %H:%M:%S"))

def subtract(list):
    return list[1] - list[0]

def time_convert(secs):
    secs = int(secs)
    mins = secs // 60
    hrs = mins // 60
    return "%02d:%02d:%02d" % (hrs, mins % 60, secs % 60)

def main():
    parse_args()
    print "Fromtime : " + str(fromTime) + '\n' + "Totime : " + str(toTime)
    timelist = [ fromTime, toTime ]
    s = map(compute_time,timelist)
    d = subtract(s)
    print "diff in seconds : " + str(d)
    f = str(d).split('.')
    final = time_convert(f[0])
    print "Total difference in required format : " + str(final)

main()

Executing the above script:

$ python timediff.py -f 'Oct/09/2009  10:58:01' -t 'Oct/10/2009  12:17:10'

Output:

Fromtime : Oct/09/2009  10:58:01
Totime : Oct/10/2009  12:17:10
diff in seconds : 91149.0
Total difference in required format : 25:19:09

Related concepts and posts:

- Convert seconds to hh:mm:ss format using python
- Python time.mktime
- Python time.strftime
- Python map
- Python getopt

Python - seconds to hh-mm-ss conversion

Solution1: Using python 'time' module strftime function.

 
Python 2.5.2 (r252:60911, Jul 22 2009, 15:35:03)
[GCC 4.2.4 (Ubuntu 4.2.4-1ubuntu3)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import time
>>> time.strftime('%H:%M:%S', time.gmtime(7302))
'02:01:42'
>>> time.strftime('%H:%M:%S', time.gmtime(86399))
'23:59:59'
>>> time.strftime('%H:%M:%S', time.gmtime(86405))
'00:00:05'

So as seen above this solution works only for num seconds < 1 day (86400 seconds)

Solution2: Using python datetime module, timedelta object.

>>> import datetime
>>> x = datetime.timedelta(seconds=7302)
>>> str(x)
'2:01:42'
>>> x = datetime.timedelta(seconds=86399)
>>> str(x)
'23:59:59'
>>> x = datetime.timedelta(seconds=86405)
>>> str(x)
'1 day, 0:00:05'

Solution3: Using normal division in python

import sys

secs = int(sys.argv[1])
mins = secs // 60
hrs = mins // 60

#hh:mm:ss
print "%02d:%02d:%02d" % (hrs, mins % 60, secs % 60)

#mm:ss
print "%02d:%02d" % (mins, secs % 60)

Executing it:

$ python timeconv.py 7302
02:01:42
121:42

$ python timeconv.py 86399
23:59:59
1439:59

$ python timeconv.py 86405
24:00:05
1440:05